"1" equals "2"

[Hans]

Suppose X = 1

then :
( X-1 ) ( X+1 ) = X ( X-1 )

Divide both columns with ( X-1 ) then :
X+1 = X

Subsitute X with "1" and you`ll get :
1+1 = 1

So :
2 = 1

Maths, it`s amazing

 

[manutd4eva]

 

[Ubik Valis]

That doesn't even make sense.

 

[Hans]

It`s called arithmethic logic Dragan . . .

In the first formula, if you substitute X with 1 then both columns will equals zero, in which 0=0 is logically correct.

So if both columns has the same value when both are divided with a variable then it should be constant. For instant : 18 = 18 ; now, if you divide both columns with 2, you`ll get 9 = 9. Which is logically correct also.

But in the third formulation things are gettin` inconsistent. Both columns doesn`t have an equal value. Which is 2 =1. But the previous steps are correct according to arithmethics, but the end result is not.

 

[Ubik Valis]

Riiiiiiight

 

[Awax]

yea i've seen this in class before university (dunno how u call it)
the prof asked us to prove this, and we someone do, he pass his course at 90%.
obviously noone could :funny:

 

[Funky--K]

holy ****, that looks correct

 

[Hercules]

Suppose X = 1

then :
( X-1 ) ( X+1 ) = X ( X-1 )

Divide both columns with ( X-1 ) then :
X+1 = X (Only if X-1 is non-zero, i.e. X is not 1).


ie the above step is garbage

otherwise you will have X+1/0 = X/0

then you will have infinity=infinity which is correct.

 

[Funky--K]

true

 

[Chacarita Juniors]

what???...i thought 1=1.... ...math aint my strongest subj.

 

[hanek45]

who cares


**** MATH.

 

[Lock]

there are restrictions on the domain when so do that i think, so I think that that plays some factor in the result.

 

[AzN-TriNi]

( X-1 ) ( X+1 ) doesnt = X ( X-1 )

( X-1 ) ( X+1 ) = X^2 -1

 

[bjmenge]

Originally posted by Hans
( X-1 ) ( X+1 ) = X ( X-1 )

Wrong. Meaning your entire post is, in fact, bullshit.

 

[ShiftyPowers]

Originally posted by Hercules
Suppose X = 1

then :
( X-1 ) ( X+1 ) = X ( X-1 )

Divide both columns with ( X-1 ) then :
X+1 = X (Only if X-1 is non-zero, i.e. X is not 1).


ie the above step is garbage

otherwise you will have X+1/0 = X/0

then you will have infinity=infinity which is correct.

Yep, that's what jumped out at me too. You can NEVER EVER EVER EVER EVER divide out variables. (x^2)/x DOES NOT = x because as the case above demonstrates, you cannot divide by zero and therefore there is no answer for when x = 0, but in the equation y=x, the answer is 0.

Oh yeah, and the one bj and the other guy pointed out is correct too.

 

[Funky--K]

Originally posted by bjmenge
Wrong. Meaning your entire post is, in fact, bullshit.

true

x (x - 1) = x(square) - 1

 

[$teauA]

actually x(x-1)=x^2-x not x^2-1

 

[Vagegast]

I thought factoring is hard

 

[ShiftyPowers]

Factoring is easy, but it depends on how it is taught to you. In 8th grade I had a teacher who taught the most complicated and retarded way to factor, and I didn't understand it. In 9th Grade (repeating Algebra thank you very much ****ty 8th grade teacher) I learned it by the what two numbers multiply to equal the last number and add up to the middle number method, which is simple.

Math is ******* easy, it's just all about memorization and being careful.

 

[manutd4eva]

Originally posted by ShiftyPowers
I learned it by the what two numbers multiply to equal the last number and add up to the middle number method, which is simple.

Yup.

Also the fomula method is easy.