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"1" equals "2"

ShiftyPowers

Make America Great Again
Originally posted by Lee86
damn.. what's that maths geek's conference!?!? my head aches!!:crazyboy: :( :)

If we're math geeks for knowing simple algebra, you might as well just live in a cave without anything invented after 650 BC.
 

RUSI

El Merengue Argentino
Originally posted by ShiftyPowers
I learned it by the what two numbers multiply to equal the last number and add up to the middle number method, which is simple.

Can you give me an example ?

I don't know if I ever heard that ?
 

manutd4eva

Fan Favourite
x(squared) + 3x + 2

x = 1*1
2 = 2* 1

So:

2 * 1 = 2 and
1 * 1 = 1

Then 2 + 1 = 3 =b

So the result is: (x + 1) (x + 2)

(H)
 

ShiftyPowers

Make America Great Again
No, that's the confusing way, but I'll use the same example.

x^2 + 3x + 2

now since it's x^2 you know right away that it's going to be (x ____) (x ___), no 2's in there or anything.

Then you know that the last two numbers have to equal 2 when multiplied. You know this because the only multiplication in the FOIL that will equal something without "x", is the two "____"s.

In addition, you know that you're going to have one of the x's times the opposite "____" and the other x times the other "____", so basically since there are no coeficients you know it's essentially going to be "____" + "____", because you get two numbers that can be added together.

So you need two numbers that add up to 3 and multiply to 2. There's only one combination, and it's 2 and 1. Both numbers positive because -1 and -2 added together = -3. And no negative x's because of the same reason. You can technically have the factoring be (-x-2)(-x-1), but if you factor out a -1 out of each of those, they multiply to 1. Therefore the answer is (x+2)(x+1).

Basically if you look at a basic quadratic equation as AX^2+BX+C, you need two numbers that add up to B and multiply to C. If A is anything other than 1, then what you do is factor out that number. So if you have something like 2x^2+6x+4 then factor out a 2 and make it 2(x^2+3x+2), and then factor like normal, so it's 2(x+2)(x+1). And if you want to put the 2 back in, (2x+4)(x+1) or (2x+2)(x+2) are also acceptable.

Takes a lot to get factoring down for the first time, but once you get it, it's simple.
 
anyways,

factoring is simple stuff....


When I first got into Calculus I thought it was gonna eb a pain in the ass but it turned out to be one of my fav classes (Y)(Y)(Y)
 

Vagegast

Banned for Life [He likes P. Diddy]
Originally posted by ShiftyPowers
Factoring is easy, but it depends on how it is taught to you.
It's because I don't pay attention. I just put my head down and listen to my iPod :(


But yeah, it's not hard. And I experiended the same thing. My Algebra I teacher (9th grade) explained it and I never got it. The Algebra II teacher I have now used the middle number to explain it and it's easy (Y)
 

manutd4eva

Fan Favourite
Originally posted by ShiftyPowers
No, that's the confusing way, but I'll use the same example.

x^2 + 3x + 2

now since it's x^2 you know right away that it's going to be (x ____) (x ___), no 2's in there or anything.

Then you know that the last two numbers have to equal 2 when multiplied. You know this because the only multiplication in the FOIL that will equal something without "x", is the two "____"s.

In addition, you know that you're going to have one of the x's times the opposite "____" and the other x times the other "____", so basically since there are no coeficients you know it's essentially going to be "____" + "____", because you get two numbers that can be added together.

So you need two numbers that add up to 3 and multiply to 2. There's only one combination, and it's 2 and 1. Both numbers positive because -1 and -2 added together = -3. And no negative x's because of the same reason. You can technically have the factoring be (-x-2)(-x-1), but if you factor out a -1 out of each of those, they multiply to 1. Therefore the answer is (x+2)(x+1).

Basically if you look at a basic quadratic equation as AX^2+BX+C, you need two numbers that add up to B and multiply to C. If A is anything other than 1, then what you do is factor out that number. So if you have something like 2x^2+6x+4 then factor out a 2 and make it 2(x^2+3x+2), and then factor like normal, so it's 2(x+2)(x+1). And if you want to put the 2 back in, (2x+4)(x+1) or (2x+2)(x+2) are also acceptable.

Takes a lot to get factoring down for the first time, but once you get it, it's simple.

It's the same principle, but you just explained it more.

It took me two years to finally understand factoring, though.:( :$
 

NIDOKING

Senior Squad
Maths could solve anything, here is an example

A mother has 21 years more than his son, and in 6 years the kid will be five times younger than her age

Where's his father? :confused:

Analyzing

The kid has now X years old and his mom Y years old, also we know that his mother has 21 more years than him, so

X + 21 = Y

We know that in six years the kid will be five times younger than her age, so we now have

5 (X+ 6) = Y + 6

Now we replace Y with X + 21 and start calculating

5 (X + 6) = X + 21 + 6
5X + 30 = X + 27
5X - X = 27 - 30
4X = -3
X = -3/4

The kid is now -3/4 years old, that's equal to -9 months

By Maths, we discovered that someone is fücking the mother

Solution: The father is on his mother :o
 

$teauA

Superstar
Originally posted by NIDOKING
Maths could solve anything, here is an example

A mother has 21 years more than his son, and in 6 years the kid will be five times younger than her age

Where's his father? :confused:

Analyzing

The kid has now X years old and his mom Y years old, also we know that his mother has 21 more years than him, so

X + 21 = Y

We know that in six years the kid will be five times younger than her age, so we now have

5 (X+ 6) = Y + 6

Now we replace Y with X + 21 and start calculating

5 (X + 6) = X + 21 + 6
5X + 30 = X + 27
5X - X = 27 - 30
4X = -3
X = -3/4

The kid is now -3/4 years old, that's equal to -9 months

By Maths, we discovered that someone is fücking the mother

Solution: The father is on his mother :o

I gotta show that one to ma precal teacher, he'll love it (H) :rockman:
 

Hans

How big is YOUR penis?
How `bout this :
According to calculus :
ln(l+x) = x-(1/2)x^2 + (1/3)x^2 - (1/4)X^2+. . .
for -1<x<=1

Subsitute the x`s in the first formula with "1" so we get :
ln2 = 1-1/2+1/3-1/4+1/5-1/6+1/7-1/8+1/9-1/10+. . .

and then :
2 X ln2 = 2 X (1-1/2+1/3+1/4+1/5+1/6+1/7+1/8+1/9+1/10+. . .)

So we`ll get :
2ln2 = 2-1+2/3-1/2+2/5-1/3+2/7-1/4+2/9-1/5+...

Or it can be written :
2ln2=(2-1)-1/2+(2/3-1/3)-1/4+(2/5-1/5)- . . .
2ln2= 1-1/2+1/3-1/4+1/5-. . . ( which is equals ln2 from above )

So :
2ln2=ln2

Divide both columns with ln2, we`ll get :
2=1
 

leungtl

Manager
Staff member
Hans, are you just copying and pasting from another source.

Because you don't really show much understanding in this topic :(
 

FF7

Senior Squad
Originally posted by NIDOKING
Maths could solve anything, here is an example

A mother has 21 years more than his son, and in 6 years the kid will be five times younger than her age

Where's his father? :confused:

Analyzing

The kid has now X years old and his mom Y years old, also we know that his mother has 21 more years than him, so

X + 21 = Y

We know that in six years the kid will be five times younger than her age, so we now have

5 (X+ 6) = Y + 6

Now we replace Y with X + 21 and start calculating

5 (X + 6) = X + 21 + 6
5X + 30 = X + 27
5X - X = 27 - 30
4X = -3
X = -3/4

The kid is now -3/4 years old, that's equal to -9 months

By Maths, we discovered that someone is fücking the mother

Solution: The father is on his mother :o



haha great :D
 

bjmenge

The Man From Ohio
Guys, this is the only formula you really need to know.



(H)
 

Hans

How big is YOUR penis?
Originally posted by leungtl
Hans, are you just copying and pasting from another source.

Because you don't really show much understanding in this topic :(
I got them from my professor :( He is a bit psycho . . .
 

jatin

Reserve Team
Of course he is
And he needs to inprove
U cant cancel (x-1) from both sides unless its non-zero..i.e-X!=1:f***:
 

ShiftyPowers

Make America Great Again
Originally posted by jatin
U cant cancel (x-1) from both sides unless its non-zero..i.e-X!=1:f***:

Yes, I think we've sufficiently covered that in the previous 36 posts, but thanks anyway Jatin.
 

RUSI

El Merengue Argentino
Originally posted by RUSI
Can you give me an example ?

I don't know if I ever heard that ?

Oh.

I did not know you were talking about factoring. :$

I just call it foil. my bad


That's a good explanation though. (Y)


back to math...

I hate having to factor shit like this (X^n - Y^n)
 


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